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PHP show_source() Function

< PHP Misc Reference

Example

Using a test file ("test.php") to output the file with the PHP syntax highlighted:

<html>
<body>
<?php
show_source("test.php");
?>
</body>
</html>

The browser output of the code above could be (depending on the content in your file):

<html>
<body>
<?php
echo ("test.php");
?>
</body>
</html>

The HTML output of the code above could be (View Source):

<html>
<body>
<code><span style="color: #000000">
<html>
<br /><body>
<br /><span style="color: #0000BB"><?php
<br /></span><span style="color: #007700">echo (</span><span style="color: #DD0000">"test.php"</span><span style="color: #007700">);
<br /></span><span style="color: #0000BB">?>
<br /></span></body>
<br /></html></span>
</code>
</body>
</html>

Definition and Usage

The show_source() function outputs a file with the PHP syntax highlighted. The syntax is highlighted by using HTML tags.

The colors used for highlighting can be set in the php.ini file or with the ini_set() function.

show_source() is an alias of highlight_file().

Note: When using this function, the entire file will be displayed - including passwords and any other sensitive information!

Syntax

show_source(filename,return)

Parameter	Description
filename	Required. Specifies the file to display
return	Optional. If this parameter is set to TRUE, this function will return the highlighted code as a string, instead of printing it out. Default is FALSE

Technical Details

Return Value:	If the return parameter is set to TRUE, this function returns the highlighted code as a string instead of printing it out. Otherwise, it returns TRUE on success, or FALSE on failure
PHP Version:	4+
Changelog:	As of PHP 4.2.1, this function is now also affected by safe_mode and open_basedir. However, safe_mode was removed in PHP 5.4. The return parameter was added in PHP 4.2.0.

< PHP Misc Reference