编辑代码:
查看结果 »
试一试 - ©
w3ii.com
<!DOCTYPE html> <html> <body> <h2>AJAX</h2> <button type="button" onclick="loadDoc()">Request data</button> <p>Click the button several times to see if the time changes, or if the file is cached.</p> <p id="demo"></p> <script> function loadDoc() { var xhttp = new XMLHttpRequest(); xhttp.onreadystatechange=function() { if (xhttp.readyState == 4 && xhttp.status == 200) { document.getElementById("demo").innerHTML = xhttp.responseText; } }; xhttp.open("GET", "demo_get.asp?t=" + Math.random(), true); xhttp.send(); } </script> </body> </html>